如何提取數(shù)組中的公共元素分別放到兩個(gè)數(shù)組？

var arr = ["2018-04-17T03", "2018-04-18T15", "2018-04-17T04", "2018-04-18T16", "2018-04-17T05", "2018-04-18T17", "2018-04-17T06", "2018-04-17T07", "2018-04-17T08", "2018-04-17T09", "2018-04-17T20", "2018-04-18T10", "2018-04-17T21", "2018-04-18T11", "2018-04-17T00", "2018-04-17T22", "2018-04-18T12", "2018-04-17T01", "2018-04-17T23", "2018-04-18T13", "2018-04-17T02", "2018-04-18T14", "2018-04-17T14", "2018-04-18T04", "2018-04-17T15", "2018-04-18T05", "2018-04-17T16", "2018-04-18T06", "2018-04-17T17", "2018-04-18T07", "2018-04-17T18", "2018-04-18T08", "2018-04-17T19", "2018-04-18T09", "2018-04-17T10", "2018-04-18T00", "2018-04-17T11", "2018-04-18T01", "2018-04-17T12", "2018-04-18T02", "2018-04-17T13", "2018-04-18T03"];

arr 中的每一個(gè)元素后三位不同，我想將每個(gè)元素前面十位相同的截取到一個(gè)數(shù)組，不同的放到另一個(gè)數(shù)組

回答

編輯回答

拼未來(lái)

const arr = ["2018-04-17T03", "2018-04-18T15", "2018-04-17T04", "2018-04-18T16", "2018-04-17T05", "2018-04-18T17", "2018-04-17T06", "2018-04-17T07", "2018-04-17T08", "2018-04-17T09", "2018-04-17T20", "2018-04-18T10", "2018-04-17T21", "2018-04-18T11", "2018-04-17T00", "2018-04-17T22", "2018-04-18T12", "2018-04-17T01", "2018-04-17T23", "2018-04-18T13", "2018-04-17T02", "2018-04-18T14", "2018-04-17T14", "2018-04-18T04", "2018-04-17T15", "2018-04-18T05", "2018-04-17T16", "2018-04-18T06", "2018-04-17T17", "2018-04-18T07", "2018-04-17T18", "2018-04-18T08", "2018-04-17T19", "2018-04-18T09", "2018-04-17T10", "2018-04-18T00", "2018-04-17T11", "2018-04-18T01", "2018-04-17T12", "2018-04-18T02", "2018-04-17T13", "2018-04-18T03"];
const prefix = '2018-04-17';  // 這個(gè)是相通的前綴，可以換
const samePrefix = []; // 存放相同前綴的數(shù)組
const others = []; // 存放不同前綴的數(shù)組
arr.forEach(date=>{
    if (date.substring(0,10) === prefix) {
        samePrefix.push(date)
    } else {
        others.push(date);
    }
})

2017年10月28日 15:39

編輯回答

我甘愿

var arr = ["2018-04-17T03", "2018-04-18T15", "2018-04-17T04", "2018-04-18T16", "2018-04-17T05", "2018-04-18T17", "2018-04-17T06", "2018-04-17T07", "2018-04-17T08", "2018-04-17T09", "2018-04-17T20", "2018-04-18T10", "2018-04-17T21", "2018-04-18T11", "2018-04-17T00", "2018-04-17T22", "2018-04-18T12", "2018-04-17T01", "2018-04-17T23", "2018-04-18T13", "2018-04-17T02", "2018-04-18T14", "2018-04-17T14", "2018-04-18T04", "2018-04-17T15", "2018-04-18T05", "2018-04-17T16", "2018-04-18T06", "2018-04-17T17", "2018-04-18T07", "2018-04-17T18", "2018-04-18T08", "2018-04-17T19", "2018-04-18T09", "2018-04-17T10", "2018-04-18T00", "2018-04-17T11", "2018-04-18T01", "2018-04-17T12", "2018-04-18T02", "2018-04-17T13", "2018-04-18T03"];
    const result=arr.reduce((obj,item)=>{
        const key=item.substring(0,10);
        if(!obj[key]){
            obj[key]=[];
        }
        obj[key].push(item);
        return obj;
    },{});
    const _result=Object.keys(result).map(key=>result[key]);
    console.log(_result);

2017年12月19日 02:48