鍍金池/ 問答/PHP/ php計算一月中有多少個周末

php計算一月中有多少個周末

找到的一個方案如下：

function get_weekend_days($start_date, $end_date, $weekend_days=1) {

    $data = array();

    $start_reduce = $end_add = 0;
    $start_N      = date('N',strtotime($start_date));
    $start_reduce = ($start_N == 7) ? 1 : 0;

    $end_N = date('N',strtotime($end_date));

    // 進行單、雙休判斷，默認按單休計算
    $weekend_days = intval($weekend_days);
    switch ($weekend_days)
    {
        case 2:
            in_array($end_N,array(6,7)) && $end_add = ($end_N == 7) ? 2 : 1;
            break;
        case 1:
        default:
            $end_add = ($end_N == 7) ? 1 : 0;
            break;
    }

    $days = ((strtotime($end_date) - strtotime($start_date))/86400) + 1;
    $data['total_days'] = $days;
    $data['total_relax'] = floor(($days + $start_N - 1 - $end_N) / 7) * $weekend_days - $start_reduce + $end_add;

    return $data;
}

這個$data['total_relax'] 為什么要這樣計算呢？ 這方法好像不太好用，比如今天 是周天 但是返回的$data['total_relax']是0

回答
編輯回答
你好胸

試試這個修改過的

<?php

function get_weekend_days($start_date, $end_date, $weekend_days=1) {

$data = array();

$start_reduce = $end_add = 0;
$start_N      = date('N',strtotime($start_date));


$end_N = date('N',strtotime($end_date));

// 進行單、雙休判斷，默認按單休計算
$weekend_days = intval($weekend_days);
switch ($weekend_days)
{
    case 2:
        in_array($end_N,array(6,7)) && $end_add = ($end_N == 7) ? 2 : 1;
        $start_reduce = ($start_N == 7) ? 1 : 0;
        break;
    case 1:
    default:
        $end_add = ($end_N == 7) ? 1 : 0;
        break;
}

$days = ((strtotime($end_date) - strtotime($start_date))/86400) + 1;
$data['total_days'] = $days;
$data['total_relax'] = floor(($days + $start_N - 1 - $end_N) / 7) * $weekend_days - $start_reduce + $end_add;

return $data;
}

echo "Two days per week\n";
var_dump( get_weekend_days("2018-03-31","2018-04-08",2));
var_dump( get_weekend_days("2018-04-01","2018-04-08",2));
var_dump( get_weekend_days("2018-04-02","2018-04-08",2));
var_dump( get_weekend_days("2018-04-07","2018-04-08",2));
var_dump( get_weekend_days("2018-04-08","2018-04-08",2));
echo "One day per week\n";
var_dump( get_weekend_days("2018-03-31","2018-04-08",1));
var_dump( get_weekend_days("2018-04-01","2018-04-08",1));
var_dump( get_weekend_days("2018-04-02","2018-04-08",1));
var_dump( get_weekend_days("2018-04-07","2018-04-08",1));
var_dump( get_weekend_days("2018-04-08","2018-04-08",1));
2017年6月24日 18:56