如上圖所示,現(xiàn)有一個(gè)通過linux命令返回的多行字符串,需要切開INCLUDE列下每一行第一個(gè)'CLA',并統(tǒng)計(jì)出所有的行中INCLUDE列下返回的'CLA'(每一行僅限第一個(gè))的總數(shù)量.我的代碼如下:
import re
ss = '+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ n| ID | NAME | DESCRIPTION | INCLUDE | ROLLBACK | n+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ n| 1481439 | CSS Upgrade Patch | Upgrade CSS to R9A for case | CLA#1481439 | True | n| 1501340 | Artifact CLA#1501340 ZBX Ansi| support ZBX Ansible Module Ex| CLA#1501340v6.1.5 CLA#1499108v6.1.0 | True | n| 1527137 | Artifact CLA#1527137v6.1.2 PR| support CMCC PRMTOOL Feature | CLA#1527137v6.1.2 | True |.........'
for line in ss.split('n')[3:]:
info = line[1:-1].split('|')
a=re.search(r'(.*?)CLA', info[3])
b = a.group()
print b
c = b.count('CLA')
print c
得到結(jié)果如下:
CLA
1
CLA
1
CLA
1
我的問題是:已經(jīng)通過正則匹配到了表中擁有的3個(gè)CLA的字符串,但統(tǒng)計(jì)時(shí)卻只統(tǒng)計(jì)到了3個(gè)1,如何通過代碼達(dá)成總數(shù)為3的返回值呢?謝謝.
看到 linux命令返回
,我第一感覺就是可以直接通過 命令解決,你可以試下:
xxxx | awk -F '|' '$5~/^ *CLA#/{n++}END{print n}'
如果非要用python
,直接復(fù)制部分文檔上來吧:
import re
ss = '+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ n| ID | NAME | DESCRIPTION | INCLUDE | ROLLBACK | n+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ n| 1481439 | CSS Upgrade Patch | Upgrade CSS to R9A for case | CLA#1481439 | True | n| 1501340 | Artifact CLA#1501340 ZBX Ansi| support ZBX Ansible Module Ex| CLA#1501340v6.1.5 CLA#1499108v6.1.0 | True | n| 1527137 | Artifact CLA#1527137v6.1.2 PR| support CMCC PRMTOOL Feature | CLA#1527137v6.1.2 | True |.........'
print len(re.findall('\| CLA#', ss, re.M))
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