在C++語言中,我們可以通過循環(huán)以及switch case
的幫助將數(shù)字轉(zhuǎn)換字符數(shù)。 在這個(gè)程序中,我們從用戶那里獲取輸入,并迭代這個(gè)數(shù),直到它為0
。在迭代時(shí)將它除以10
,余數(shù)傳遞在switch case
中,最后得到數(shù)字的字符形式。
下面來看看看C++程序?qū)?shù)字轉(zhuǎn)換字符數(shù)字形式。
#include <iostream>
using namespace std;
int main()
{
long int n,sum=0,r;
cout<<"Enter the Number= ";
cin>>n;
while(n>0)
{
r=n%10;
sum=sum*10+r;
n=n/10;
}
n=sum;
while(n>0)
{
r=n%10;
switch(r)
{
case 1:
cout<<"one ";
break;
case 2:
cout<<"two ";
break;
case 3:
cout<<"three ";
break;
case 4:
cout<<"four ";
break;
case 5:
cout<<"five ";
break;
case 6:
cout<<"six ";
break;
case 7:
cout<<"seven ";
break;
case 8:
cout<<"eight ";
break;
case 9:
cout<<"nine ";
break;
case 0:
cout<<"zero ";
break;
default:
cout<<"tttt ";
break;
}
n=n/10;
}
return 0;
}
執(zhí)行上面代碼得到以下結(jié)果 -
Enter the Number= 74254
seven four two five four